Message-ID:	<3E2726AB.9030704@earthlink.net>
From:	Martin Ambuhl <mambuhl AT earthlink DOT net>
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Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: sizeof(struct x) doesn't compile -- how to do it ?
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Date:	Thu, 16 Jan 2003 21:40:16 GMT
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

Lars Hansen wrote:
> #include "stdlib.h"
> 
> struct x
>  {
>   double x;
>  };
> 
> int main()
>  {
>   x* n=malloc(2*sizeof(struct x));
>  }
> 
> 
> produces the following compiler error message:
> 
> test.c: In function `main':
> test.c:10: `x' undeclared (first use in this function)
> test.c:10: (Each undeclared identifier is reported only once
> test.c:10: for each function it appears in.)
> test.c:10: `n' undeclared (first use in this function)
> 
> 
> So how do I get the size of structs with djgpp?
#include <stdlib.h>

struct x
{
     double x;
};

int main()
{
     struct x *n = malloc(2 * sizeof(struct x));
}

> 
> And also: if i have an array of a struct with several elements how can i know
> at which byte an element of the nth struct is in that array with djgpp (eg
> after writing a struct array to file and then loading this data without
> knowing how to "synchronize" djgpps compiler struct array generation and
> saving and an other compilers array struct generation and loading means one
> best knows the byte position (and length))

Lookup offsetof()

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