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| From: | those who know me have no need of my name <not-a-real-address AT usa DOT net> |
| Newsgroups: | alt.comp.lang.learn.c-c++,comp.lang.c++,comp.os.msdos.djgpp |
| Subject: | Re: char[] & non-Latin letters |
| Followup-To: | alt.comp.lang.learn.c-c++ |
| Date: | 28 Aug 2002 03:43:05 GMT |
| Organization: | earthfriends |
| Message-ID: | <umohmcebcrjr94@news.supernews.com> |
| References: | <akdr5h$1hk2er$1 AT ID-79865 DOT news DOT dfncis DOT de> <3D6B432F DOT 4552DB3E AT mail1 DOT stofanet DOT dk> |
| <akgl7a$1i2cm0$1 AT ID-79865 DOT news DOT dfncis DOT de> | |
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| Lines: | 27 |
| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
| Reply-To: | djgpp AT delorie DOT com |
[fu-t set] in alt.comp.lang.learn.c-c++ i read: >#define TEST_VALUE 65 > >char c_value = TEST_VALUE; >wchar_t wc_value = TEST_VALUE; you presume too much. you think you know that 65 is a character, but there is no guarantee that it is, whether you use char or wchar_t -- you have no idea what that encoding may be used. use character literals when you mean to initialize character variables, e.g., char c_value = 'A'; wchar_t wc_value = L'A'; > cout << c_value << endl; > cout << wc_value << endl; wcout << wc_value << endl; yes it's cumbersome that cout doesn't adapt to wide arguments, but that's life. -- bringing you boring signatures for 17 years
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