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From: | Richard Dawe <rich AT phekda DOT freeserve DOT co DOT uk> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: GNU Pascal (gpc) 2.1 released |
Date: | Fri, 24 May 2002 21:51:10 +0100 |
Lines: | 25 |
Message-ID: | <3CEEA7BE.8E036E64@phekda.freeserve.co.uk> |
References: | <Pine DOT SUN DOT 3 DOT 91 DOT 1020523191611 DOT 3394B-100000 AT is> <3CED528D DOT 7DCF9660 AT yahoo DOT com> <3CED6BA6 DOT 48D4D0FE AT phekda DOT freeserve DOT co DOT uk> <ackpus$4e5$1 AT antares DOT lu DOT erisoft DOT se> <200205241404 DOT g4OE4Qt03777 AT envy DOT delorie DOT com> <3CEE7DCE DOT BD8CACAE AT yahoo DOT com> |
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To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
Hello. CBFalconer wrote: [snip] > Which means that "rm @foo" cannot mean to remove the file "@foo", > because if it exists it is an extended command line, and if it > doesn't it becomes an argument. So, at least for rm, that usage > makes no sense. For other programs it is another matter. [snip] FWIW this works analogously to shell wildcards do. In bash try: rm -v somefilethatdoesnotexist*.foo where nothing matches the wildcard. You should find that 'somefilethatdoesnotexist*.foo' is not expanded, because it doesn't match anything. I'm not saying this behaviour makes sense, just that the treatment of '@foo' is analogous. Regards, -- Richard Dawe [ http://www.phekda.freeserve.co.uk/richdawe/ ]
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