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| From: | "A. Sinan Unur" <asu1 AT cornell DOT edu> |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: Newbie Division Operator Question |
| Date: | 14 Mar 2002 13:14:17 GMT |
| Organization: | Cornell University |
| Lines: | 46 |
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| NNTP-Posting-Date: | 14 Mar 2002 13:14:17 GMT |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
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zandro_arceo AT support DOT trendmicro DOT com (IeperNaum) wrote in
news:d26d20a2 DOT 0203140257 DOT 6365ae0e AT posting DOT google DOT com:
> #define __int64 long long
>
> unsigned __int64 x = 268486768;
>
> unsigned __int64 y = x/10000000;
>
> i expect y = 26
> but y = 4065811060.
>
> can anybody please explain to me why?
it is either the #define rather than typedef getting in your way, or you
are not specifying the conversion specifier in printf correctly.
read the printf docs by invoking info in the following way:
info libc alpha printf
C:\develop\src\misc>cat d.c
#include <stdio.h>
typedef unsigned long long myuint64;
static void doit(void)
{
myuint64 x = 268486768;
myuint64 y = x/10000000;
printf("y = %llu\n", y);
return;
}
int main(void)
{
doit();
return 0;
}
C:\develop\src\misc>gcc -Wall d.c -o d.exe
C:\develop\src\misc>d
y = 26
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