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From: | "A. Sinan Unur" <asu1 AT cornell DOT edu> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: Newbie Division Operator Question |
Date: | 14 Mar 2002 13:14:17 GMT |
Organization: | Cornell University |
Lines: | 46 |
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NNTP-Posting-Date: | 14 Mar 2002 13:14:17 GMT |
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To: | djgpp AT delorie DOT com |
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zandro_arceo AT support DOT trendmicro DOT com (IeperNaum) wrote in news:d26d20a2 DOT 0203140257 DOT 6365ae0e AT posting DOT google DOT com: > #define __int64 long long > > unsigned __int64 x = 268486768; > > unsigned __int64 y = x/10000000; > > i expect y = 26 > but y = 4065811060. > > can anybody please explain to me why? it is either the #define rather than typedef getting in your way, or you are not specifying the conversion specifier in printf correctly. read the printf docs by invoking info in the following way: info libc alpha printf C:\develop\src\misc>cat d.c #include <stdio.h> typedef unsigned long long myuint64; static void doit(void) { myuint64 x = 268486768; myuint64 y = x/10000000; printf("y = %llu\n", y); return; } int main(void) { doit(); return 0; } C:\develop\src\misc>gcc -Wall d.c -o d.exe C:\develop\src\misc>d y = 26
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