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From:	"Tim Nicholson" <djgpp AT gizzy DOT co DOT uk>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: arrays in an array
Date:	Sun, 17 Feb 2002 22:35:05 +0000 (UTC)
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To access the third element of the second element of the array a1 - You
enter a1[1][2] - This is almost what you had but without the dot and the
fact that *each* array starts at zero so the third element is 2 not 3.

If you wanted an array of 10 elements each containing an array of 12
integers the definition would be

int a1[10][12];      and the last element in the array would be a1[9][11]

With out knowing what you really want to achieve, I cannot offer much more
assistance. Why do you say you do not want to use multidimensional arrays?
What you drew is a multidimensional array! - If you could explain your
reasoning, I might be able to offer alternative solutions.

Tim


"PM" <sendto DOT paulm AT sympatico DOT ca> wrote in message
news:PyUb8.5637$I01 DOT 244480 AT news20 DOT bellglobal DOT com...
> hey there im having a little bit of a coding problem.. ive got the
algorithm
> down but cant figure out the coding part.
>
> heres what i wanna do.. i would like to access an array element whos array
> is an element itself.. for example
>
> lets say we have an array a1, whos elements are arrays
>
> _______________________
> |___|____|___|___|____|___|
> and inside these elements there are more arrays
> |___||___||___||___||___||___|
> |___||___||___||___||___||___|
> |___||___||___||___||___||___|
> |___||___||___||___||___||___|
>
> my question is this..
> how would i be able to access.. say the 3rd element in the 2nd element of
> the array?
> eg.
> _______________________
> |___|__o_|___|___|____|___|
>            V
> |___||___||___||___||___||___|
> |___||___||___||___||___||___|
> |___||_o_||___||___||___||___|
> |___||___||___||___||___||___|
>
> would i do something like this??
> a1[1].[3] or soemthing like that??
>
> plus, i dont want to set it up as a multidimensional array. because im
> trying to simulate grocery store checkout stations.
>
> Please, I would appretiate any help!!
>
> Thanks,
> Paul M.
>
>

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