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| Message-ID: | <002901c19c89$4f71df80$2de1a0c8@rjo.virtua.com.br> |
| From: | "Pedro Izecksohn" <izecksohn AT yahoo DOT com> |
| To: | <djgpp AT delorie DOT com> |
| Subject: | return 1; |
| Date: | Sun, 13 Jan 2002 21:23:20 -0200 |
| MIME-Version: | 1.0 |
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| X-MSMail-Priority: | Normal |
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| Disposition-Notification-To: | "Pedro Izecksohn" <izecksohn AT yahoo DOT com> |
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| Reply-To: | djgpp AT delorie DOT com |
This is a multi-part message in MIME format.
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Content-Type: text/plain;
charset="Windows-1252"
Content-Transfer-Encoding: 7bit
Hi, What do happen when main return 1 ? Does the program passes this
value to DOS's ERRORLEVEL ? Why in my code errorlevel isn't catching the 1
value ? I'm attaching here the .cc and the .bat codes. The .bat file is
renamed to .txt to pass thru the file filter, so to do it work rename it
back to .bat .
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Content-Type: text/plain;
name="terl.txt"
Content-Transfer-Encoding: 7bit
Content-Disposition: attachment;
filename="terl.txt"
erl
if errorlevel 1 echo 1
if errorlevel 0 echo 0
------=_NextPart_000_0026_01C19C78.868A3E60
Content-Type: application/octet-stream;
name="ERL.CC"
Content-Transfer-Encoding: 7bit
Content-Disposition: attachment;
filename="ERL.CC"
int main () {
return 1;
}
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