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Date:	Tue, 23 Oct 2001 07:57:09 -0500
From:	JT Williams <jeffw AT darwin DOT sfbr DOT org>
To:	djgpp AT delorie DOT com
Cc:	"Mark E." <snowball3 AT bigfoot DOT com>
Subject:	Re: bash 2.04: $# not preserved?
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-: So -- going by the comment quoted above -- the Solaris example does
-: seem to report the correct value, but I can't find any code in Bash
-: that detects when the "dollar vars" have changed and behave like the
-: Solaris example.

It seems to be tied up with DESTRUCTIVE, in builtins/common.c (see
below).  Every instance of remember_args that I can find is called with
destructive=1, but it isn't clear (to me) if that is responsible for
the observed behavior.

jtw

---

/* Remember LIST in $0 ... $9, and REST_OF_ARGS.  If DESTRUCTIVE is
   non-zero, then discard whatever the existing arguments are, else
   only discard the ones that are to be replaced. */
void
remember_args (list, destructive)
     WORD_LIST *list;
     int destructive;
{
  register int i;

  for (i = 1; i < 10; i++)
    {
      if ((destructive || list) && dollar_vars[i])
        {
          free (dollar_vars[i]);
          dollar_vars[i] = (char *)NULL;
        }

      if (list)
        {
          dollar_vars[i] = savestring (list->word->word);
          list = list->next;
        }
    }

  /* If arguments remain, assign them to REST_OF_ARGS.
     Note that copy_word_list (NULL) returns NULL, and
     that dispose_words (NULL) does nothing. */
  if (destructive || list)
    {
      dispose_words (rest_of_args);
      rest_of_args = copy_word_list (list);
    }

  if (destructive)
    set_dollar_vars_changed ();
}

- Raw text -