Date:	Mon, 27 Aug 2001 22:56:59 +0200
From:	Andrea Mazzoleni <am AT mediacom DOT it>
To:	djgpp AT delorie DOT com
Subject:	Re: Program, uses compare() to check for anagrams, but doesnt work
Message-ID:	<20010827225659.A2180@mediacom.it>
References:	<3B8AEFEF AT MailAndNews DOT com>
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In-Reply-To:	<3B8AEFEF@MailAndNews.com>; from Ramiman12@MailAndNews.com on Mon, Aug 27, 2001 at 01:29:08PM -0400
Reply-To:	djgpp AT delorie DOT com
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On Mon, Aug 27, 2001 at 01:29:08PM -0400, Ramy Elmeligy wrote:
>    for( ; a < greater, equal == 0 ; a++)
>      {
>       input1.substr(a, b).compare(input2, c, b);
>      }
This is an infinite loop. equal is always 0. Probably your intention was to
write something like :

for( ; a < greater && equal == 0 ; a++)
	equal = input1.substr(a, b).compare(input2, c, b);


Anyway this is a simpler implementation:

----------------------------------------------
#include <algorithm>
#include <string>

using namespace std;

bool is_anagram(string a, string b) {
        sort(a.begin(),a.end());
        sort(b.begin(),b.end());
        return a == b;
}

int main() {
        cout << is_anagram("aba","baa") << endl;
        return 0;
}
----------------------------------------------
					
-- 
Andrea Mazzoleni <am AT mediacom DOT it>
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