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Date: | Sun, 24 Jun 2001 17:38:16 -0400 |
Message-Id: | <200106242138.RAA18013@envy.delorie.com> |
X-Authentication-Warning: | envy.delorie.com: dj set sender to dj AT envy DOT delorie DOT com using -f |
From: | DJ Delorie <dj AT delorie DOT com> |
To: | djgpp AT delorie DOT com |
In-reply-to: | <9dde68b7.0106241053.2a385311@posting.google.com> |
(zacharyshort AT hotmail DOT com) | |
Subject: | Re: DJGPP reserves wrong int size |
References: | <9dde68b7 DOT 0106241053 DOT 2a385311 AT posting DOT google DOT com> |
Reply-To: | djgpp AT delorie DOT com |
Errors-To: | nobody AT delorie DOT com |
X-Mailing-List: | djgpp AT delorie DOT com |
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> 00000000 55 push ebp > 00000001 89E5 mov ebp,esp > 00000003 83EC04 sub esp,byte +0x18 > 00000006 C745FC78563412 mov dword [ebp-0x4],0x12345678 > 0000000D C9 leave > 0000000E C3 ret > > The third line reserves 18 bytes. > And it should reserve 4 bytes because thats the size of an int right? > If you declare a char it still reserves 18 bytes. > Could someone tell me what's going on? I am loosing my mind! > Line 4 is correct though. The purpose of that is to keep the stack aligned to a 32 byte boundary, which improves performance on today's high-end processors. 4 (the call) + 4 (the push) + 24 (the sub) = 32 You can change that with command line options (-mpreferred-stack-boundary=)
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