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From: | Hans-Bernhard Broeker <broeker AT physik DOT rwth-aachen DOT de> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: Initializing arrays problem |
Date: | 22 May 2001 17:39:22 GMT |
Organization: | Aachen University of Technology (RWTH) |
Lines: | 21 |
Message-ID: | <9ee88a$bgu$1@nets3.rz.RWTH-Aachen.DE> |
References: | <20010522124331 DOT 00567 DOT 00000895 AT ng-mi1 DOT aol DOT com> |
NNTP-Posting-Host: | acp3bf.physik.rwth-aachen.de |
X-Trace: | nets3.rz.RWTH-Aachen.DE 990553162 11806 137.226.32.75 (22 May 2001 17:39:22 GMT) |
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NNTP-Posting-Date: | 22 May 2001 17:39:22 GMT |
Originator: | broeker@ |
To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
WCount12 <wcount12 AT aol DOT com> wrote: > I am getting an error message "numeric constant contains digits beyond the > radix" when initializing the below. > int days_array = { 0101,0102,0103,0104 .........}; You've been hit by a feature of C, here: octal constants. Every integer constant that begins with a '0' is interpreted as a number in the octal, rather than the decimal system. I.e. 0101 == 8^2 * 1 + 8^0 * 1 = 64 + 1 = 65 not 0101 == 10^2 * 1 + 10^0 * 1 = 100 + 1 = 101 In octal constants, digits 8 and 9 are forbidden, thus the warning you got. -- Hans-Bernhard Broeker (broeker AT physik DOT rwth-aachen DOT de) Even if all the snow were burnt, ashes would remain.
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