From:	"Alexei A. Frounze" <dummy_addressee AT hotmail DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Printing function pointers
Date:	Fri, 20 Apr 2001 18:07:08 -0400
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"Dennis Yelle" <dennis51 AT jps DOT net> wrote in message
news:3AE082F7 DOT B4E9C05 AT jps DOT net...
> I was surprised by the output from this program:
> ---------------------
> #include <iostream>
>
> int junk1() { return 111; }
>
> int junk2() { return 222; }
>
> int main()
> {
>   if ( junk1 != junk2 ) {
>     cout << "different\n";
>   }
>   cout << junk1 << '\n';
>   cout << junk2 << '\n';
>   return 0;
> }
> ----------------------
>
> I got this:
> ----------------
> different
> 1
> 1
> ---------------
>
> So, the function pointers are different, but
> they both print as 1.  Is this expected, and desired
> behavior?  Or is it a bug?

have you tried to add () to junk1 and junk2? like this: junk1() != junk2()
and in the rest of the code?

Good Luck
--
Alexei A. Frounze
alexfru [AT] chat [DOT] ru
http://alexfru.chat.ru
http://members.xoom.com/alexfru/
http://welcome.to/pmode/

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