From:	"Wormy" <wormy AT technologist DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	How would I build a pointer to a method of my class
Date:	Sun, 8 Apr 2001 11:16:25 +0200
Organization:	University of Economics and Business Administration, Vienna, Austria
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To:	djgpp AT delorie DOT com
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Reply-To:	djgpp AT delorie DOT com

Hello all!

In simple C, I would do something like this:


-------------------------------------------
typedef void (My_func)(short parameter);

My_func Pointer_to_My_func;
-------------------------------------------

and then, later in my code (DOTHIS_func and DOTHAT_func are declared and
defined somewhere)

-------------------------------------------
if (i == 0)
    Pointer_to_My_func = DOTHIS_func;
else
    Pointer_to_My_func = DOTHAT_func;

(*Pointer_to_My_func)(parameter_to_pass);
----------------------------------------------

OK.... but now, how am I doing it in C++ if I'm fumbling around with a
class?

------------
class CMy_class
{
    void DOTHIS_method(short parameter);
    void DOTHAT_method(short parameter);

    void ANOTHER_method();
};

CMy_class My_class;
--------------------------------

And, in the method ANOTHER_method() I would like to set the pointer to one
of the two methods above (as I did it in C)... BUT I DON'T HAVE ANY IDEA
HOW! I wrote down a simple pseudocode below.
(NOTE: DOTHIS_method and DOTHAT_method are all methods of the same class)

-------------------------------
void ANOTHER_method()
{
.
.
.

    if (i == 1)
        pointer should point to DOTHIS_method;
     else
        pointer should point to DOTHAT_method;

    and now call the method my pointer is pointing to

.
.
.
}
-----------------------------

Can someone please give me a hint? BTW I am using VISUAL C++ 6.0 if this
problem couldn't be solved in "ANSI" C++

Thanx in advance

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