From:	Hans-Bernhard Broeker <broeker AT physik DOT rwth-aachen DOT de>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: what does the -s switch do?
Date:	9 Feb 2001 12:35:48 GMT
Organization:	Aachen University of Technology (RWTH)
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Rudolf Polzer <rpolzer AT web DOT de> wrote:
> Tom St Denis <stdenis AT compmore DOT net> schrieb Folgendes:
>> "gcc -g3 1.c -o 1.exe -s" is a bad idea :-)

> I forgot to ask,
> is "gcc -O3 -ggdb3 -o X.EXE" and then "strip -s X.EXE" equivalent to
> leaving out -ggdb3?

No. Leaving out -g{whatever} is equivalent to

	gcc -g{whatever} -o x.exe
	strip -g x.exe

Strip -g (the corresponding long option is --strip-debug) removes
exactly that part of the debugging information that gcc's -g family of
options add, compared to a default compilation.


-- 
Hans-Bernhard Broeker (broeker AT physik DOT rwth-aachen DOT de)
Even if all the snow were burnt, ashes would remain.

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