From:	"Vermin" <ratspl AT hotmail DOT com>
Newsgroups:	comp.os.msdos.djgpp
References:	<SEik5.4799$aK5 DOT 80126 AT news1 DOT online DOT no> <8mueij$hd7$1 AT nets3 DOT rz DOT RWTH-Aachen DOT DE>
Subject:	...but
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Date:	Thu, 10 Aug 2000 22:38:06 +0200
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but is it possible to have an array (or a pointer to an array) which doesn't
have a a given size (or doesn't really exist) until you define it by making
space for it in the mem...

some pseudo code:

procedure proc1(pointer pp){
  pp (points to) new array[arraySize];
}

main(){
  pointer p1;
  call proc1(p1);
}



"Hans-Bernhard Broeker" <broeker AT physik DOT rwth-aachen DOT de> wrote in message
news:8mueij$hd7$1 AT nets3 DOT rz DOT RWTH-Aachen DOT DE...
> Vermin <ratspl AT hotmail DOT com> wrote:
>
> > <1>
> > What's the difference between
>
> > char anArray[100];
>
> > and
>
> > char *anArray;
> > anArray = new (char)[100];
>
> Place of storage, and lifetime of the array. The first creates an
> array that lives on the stack, until you leave the block the
> definition is found in (or in a global data segment until program
> termination, if it's at file scope), the second creates a block that
> exists until you delete[] it, and a pointer to it with a certain
> lifetime.
>
> > <2> How can I pass an array with undefined size to a procedure, and
> > get the procedure to set the array size (C++)??
>
> You can't. Array size isn't modifiable a posteriori. You can only
> change the size of "new"ed arrays, and that only by delete[]ing them
> and "new"ing a new one.
>
> If you need a truly variable-sized array, look up the 'vector' template.
>
>
> --
> Hans-Bernhard Broeker (broeker AT physik DOT rwth-aachen DOT de)
> Even if all the snow were burnt, ashes would remain.

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