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From: | yosuke AT ccwf DOT cc DOT utexas DOT edu () |
Newsgroups: | comp.os.msdos.djgpp,comp.os.msdos.misc |
Subject: | redir.exe question |
Followup-To: | comp.os.msdos.djgpp |
Date: | 13 Jul 2000 17:41:34 GMT |
Organization: | The University of Texas at Austin; Austin, Texas |
Lines: | 38 |
Message-ID: | <8kkv0e$4co$1@geraldo.cc.utexas.edu> |
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NNTP-Posting-Date: | 13 Jul 2000 17:41:34 GMT |
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To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
I have question about redir which came with djgpp. I tested following code. #include <stdio.h> int main(){ printf("1: this is stdout\n"); fprintf(stderr,"2: this is stderr\n"); printf("3: this is stdout\n"); fprintf(stderr,"4: this is stderr\n"); } when I executed it, I get followin on screen. 1: this is stdout 2: this is stderr 3: this is stdout 4: this is stderr but when I go redir -eo a.exe > out or redir -o out -eo a.exe I got this in out. 2: this is stderr 4: this is stderr 1: this is stdout 3: this is stdout Is there any way not have stderr to be mixed into stdout? -- yosuke kimura Center for Energy and Environmental Resources The Univ. of Texas at Austin, USA
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