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| From: | yosuke AT ccwf DOT cc DOT utexas DOT edu () |
| Newsgroups: | comp.os.msdos.djgpp,comp.os.msdos.misc |
| Subject: | redir.exe question |
| Followup-To: | comp.os.msdos.djgpp |
| Date: | 13 Jul 2000 17:41:34 GMT |
| Organization: | The University of Texas at Austin; Austin, Texas |
| Lines: | 38 |
| Message-ID: | <8kkv0e$4co$1@geraldo.cc.utexas.edu> |
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| To: | djgpp AT delorie DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
| Reply-To: | djgpp AT delorie DOT com |
I have question about redir which came with djgpp.
I tested following code.
#include <stdio.h>
int main(){
printf("1: this is stdout\n");
fprintf(stderr,"2: this is stderr\n");
printf("3: this is stdout\n");
fprintf(stderr,"4: this is stderr\n");
}
when I executed it, I get followin on screen.
1: this is stdout
2: this is stderr
3: this is stdout
4: this is stderr
but when I go
redir -eo a.exe > out
or
redir -o out -eo a.exe
I got this in out.
2: this is stderr
4: this is stderr
1: this is stdout
3: this is stdout
Is there any way not have stderr to be mixed into stdout?
--
yosuke kimura
Center for Energy and Environmental Resources
The Univ. of Texas at Austin, USA
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