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From: | "Marp" <marp AT 0 DOT 0 DOT 0 DOT 0> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: DJGPP and while loop. |
Date: | Sat, 13 May 2000 22:46:30 -0400 |
Organization: | MindSpring Enterprises |
Lines: | 41 |
Message-ID: | <8fl4cb$271$1@slb3.atl.mindspring.net> |
References: | <fboT4.56105$r37 DOT 670154 AT news20 DOT bellglobal DOT com> |
NNTP-Posting-Host: | 04.30.99.9e |
X-Server-Date: | 14 May 2000 02:51:55 GMT |
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To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
"Aleks D." <user AT host DOT com> wrote in message news:fboT4.56105$r37 DOT 670154 AT news20 DOT bellglobal DOT com... > Hello, > > I am running Windows 98 and DJGPP. I am a beginner in C and am having > problems running compiled programs that include a while loop. I can > successfully compile the following code from RHIDE: > > > #include <stdio.h> > > > int main() > { > int count; > > count = 0; > > while(count < 6); This line should not have a semicolon at the end. It thinks that while count < 6 do nothing (; by itself is the null statement) and count never increases and your program loops forever. > { > printf("The value of count is %d\n", count); > count = count + 1; > } > > return 0; > } > > > But when I go and execute the compiled .exe in the /bin directory there is > no correct output displayed. I only get a cursor on the left side of the > screen. Any help will be appreciated. > >
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