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Date: | Mon, 13 Mar 2000 00:25:09 +0500 |
Message-Id: | <200003121925.AAA01180@midpec.com> |
From: | Prashant TR <tr AT midpec DOT com> |
To: | Robert S Whitlock <roberts DOT j DOT whitlock AT juno DOT com> |
CC: | djgpp AT delorie DOT com |
In-reply-to: | <20000312.125101.-765853.0.roberts.j.whitlock@juno.com> (message |
from Robert S Whitlock on Sun, 12 Mar 2000 12:50:47 -0500) | |
Subject: | Re: Inline ASM |
References: | <20000312 DOT 125101 DOT -765853 DOT 0 DOT roberts DOT j DOT whitlock AT juno DOT com> |
Reply-To: | djgpp AT delorie DOT com |
Errors-To: | dj-admin AT delorie DOT com |
X-Mailing-List: | djgpp AT delorie DOT com |
X-Unsubscribes-To: | listserv AT delorie DOT com |
Robert S Whitlock <roberts DOT j DOT whitlock AT juno DOT com> writes: > Okay, I know there's something simple I'm not getting... I just can't > find it. It's in the FAQ. There's a whole section on inline assembly. > I'm trying to inline asm this: > > mov ax, 0x03 > int 0x10 It's like this: __asm__("movw $0x3, %ax; int $0x10;"); But calling interrupts like this in protected mode is a bad idea. See the __dpmi_int functiont (type info libc alpha __dpmi_int).
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