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| Date: | Mon, 13 Mar 2000 00:25:09 +0500 |
| Message-Id: | <200003121925.AAA01180@midpec.com> |
| From: | Prashant TR <tr AT midpec DOT com> |
| To: | Robert S Whitlock <roberts DOT j DOT whitlock AT juno DOT com> |
| CC: | djgpp AT delorie DOT com |
| In-reply-to: | <20000312.125101.-765853.0.roberts.j.whitlock@juno.com> (message |
| from Robert S Whitlock on Sun, 12 Mar 2000 12:50:47 -0500) | |
| Subject: | Re: Inline ASM |
| References: | <20000312 DOT 125101 DOT -765853 DOT 0 DOT roberts DOT j DOT whitlock AT juno DOT com> |
| Reply-To: | djgpp AT delorie DOT com |
| Errors-To: | dj-admin AT delorie DOT com |
| X-Mailing-List: | djgpp AT delorie DOT com |
| X-Unsubscribes-To: | listserv AT delorie DOT com |
Robert S Whitlock <roberts DOT j DOT whitlock AT juno DOT com> writes:
> Okay, I know there's something simple I'm not getting... I just can't
> find it.
It's in the FAQ. There's a whole section on inline assembly.
> I'm trying to inline asm this:
>
> mov ax, 0x03
> int 0x10
It's like this:
__asm__("movw $0x3, %ax;
int $0x10;");
But calling interrupts like this in protected mode is a bad idea.
See the __dpmi_int functiont (type info libc alpha __dpmi_int).
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