Date:	Mon, 21 Feb 2000 22:49:22 +0500 (MVT)
From:	Prashant TR <prashant_tr AT yahoo DOT com>
X-Sender:	prashant_tr AT midpec DOT com
To:	Nite Hawk <malcolm3 AT bulloch DOT net>
cc:	djgpp AT delorie DOT com
Subject:	Re: Newbies need help too! <smile>
In-Reply-To:	<88q38n$6cf$1@news3.infoave.net>
Message-ID:	<Pine.LNX.4.10.10002212247050.998-100000@midpec.com>
MIME-Version:	1.0
Reply-To:	djgpp AT delorie DOT com
Errors-To:	dj-admin AT delorie DOT com
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On Sun, 20 Feb 2000, Nite Hawk wrote:

> 1. when I try to divide "taxPercent/100" it's value turns out to be "0" (I'm
> dividing a whole # such as 6 by 100 to get .06)

That's because you are dividing an interger by another integer. So, the
result would be an integer. You need to do 6*1.0/100 to get .06.

> 2. How do I get a variable to contain a name? (I'm trying to get a name as a
> variable, is this possible?)

char yourName[100];

To store the name:
strcpy(yourName, "Nite Hawk");

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