From:	"Newline" <front777 AT hotmail DOT com>
Newsgroups:	comp.os.msdos.djgpp
Subject:	no warning without #include
Date:	Sat, 5 Feb 2000 11:43:43 +0100
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To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp
Reply-To:	djgpp AT delorie DOT com

Hi,

I have code :

#include <stdio.h>

int main(void)
{
 char a[50];

 strcpy(a,"something");
 printf("%s\n",a);

 return 0;
}

So i used the strcpy function but not included <string.h>. When i compile
this with DJGPP gcc
I'm not able to get any warning that I didn't include string.h. Why is this
?
(I used 'gcc -c test.c -o test.o -Wall' to compile)

When I replace

strcpy(a,"something");

by

stupid_name(a,"something");

gcc gives me indeed the warning of implicit declared function.

also if I keep strcpy but change the type of a to eg an int, the compiler
also warns me about incompatible types.

So to me it sems as if the compiler knows of the type of strcpy even without
<string.h>

Can someone explain ?

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