Date:	Mon, 24 Jan 2000 09:29:15 +0200 (IST)
From:	Eli Zaretskii <eliz AT is DOT elta DOT co DOT il>
X-Sender:	eliz AT is
To:	David Cleaver <davidis AT ou DOT edu>
cc:	djgpp AT delorie DOT com
Subject:	Re: Weird output of printf()
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On Sun, 23 Jan 2000, David Cleaver wrote:

> fprintf(out, "%#x", array0[looper1][looper2]);
> where array0 contains unsigned char's
> 
> Anyway,  does the compiler actually think that 0xf is the same as 0x0f? 
> I personally think it should print out the leading zero

If you want the leading zero, use "%#0x" as your format specifier.  
`fprintf' cannot know what do you want it to do except by looking at
the format specifier that you provide.

> So, would the compiler be able to recognize if I chaged the array:
> from {0xf, 0xf, 0x1, 0x7} to {0xff17}?

You are mixing two different things: how a value of a 8-bit byte is 
printed, and how it is packed into a 32-bit int.  A value of 0xf (15 in 
decimal) can still occupy 8 bits, even if 4 bits are enough to express 
the value of 15.

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