From:	"doug" <deleveld AT dds DOT nl>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: djgpp strangeness
Date:	23 Dec 1999 00:05:14 GMT
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Lines:	39
Message-ID:	<01bf4cda$41f7bec0$69247d81@doug>
References:	<tmU74.34$Fc6 DOT 1542 AT weber DOT videotron DOT net> <14684.897$Qz2 DOT 16629 AT wagner DOT videotron DOT net>
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To:	djgpp AT delorie DOT com
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Valkir <jfd50 AT videotron DOT ca> schreef in artikel
<14684.897$Qz2 DOT 16629 AT wagner DOT videotron DOT net>...
> Here's the code:
> int main()
> {long x,y;
>  uchar *Video;
>  Buffer=(uchar *)malloc(1920000);
>  cVesa *Vesa=(cVesa *)malloc(sizeof(cVesa));

So Vesa is a pointer to some unknown struct to some allocated memory here.

>  Video=Vesa->InitVesa();

Maybe my brain is going funny here, but you are calling a function pointer
that 
is part of the struct, but the struct has not been initialized yet.  I take
it that InitVesa 
is a function pointer that is part of the struct.  Where is this InitVesa 
function and what does it look like?

> //////// cDesktop *Deskt=(cDesktop *)malloc(sizeof(cDesktop));
>  for(x=0;x<800;x++)
>   for(y=0;y<2400;y++)
>    *(Buffer+y*800+x)=x;
> 
>  memcpy(Video,Buffer,1920000);
>  getkey();
>  Vesa->Close();

Another function call to the struct that is (as far as I can tell)
is still unitialized, i.e. filled with garbage.

>  return(0);
> }

I hope this helps

Doug Eleveld

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