Mail Archives: djgpp/1999/12/08/17:43:06
From: | "Anes Hadzic" <a DOT hadzic AT bih DOT net DOT ba>
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Newsgroups: | comp.os.msdos.djgpp
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Subject: | Re: "-1" cannot quite the prog..
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Date: | Wed, 8 Dec 1999 21:42:58 +0100
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Organization: | BIHnet News Server
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Lines: | 87
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Message-ID: | <82mjrm$qkh5@ns4.bih.net.ba>
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References: | <82j9n0$bi8$1 AT imsp026 DOT netvigator DOT com>
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NNTP-Posting-Host: | dialup1-ppp225.bih.net.ba
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To: | djgpp AT delorie DOT com
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DJ-Gateway: | from newsgroup comp.os.msdos.djgpp
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Reply-To: | djgpp AT delorie DOT com
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Jason Yip <manman AT netteens DOT net> wrote in message
news:82j9n0$bi8$1 AT imsp026 DOT netvigator DOT com...
> I wrote this prog and expect it can be quited by entering -1...
> however it shows wrong if I enter "-1"...
> What's more, when I enter a wrong answer.. the answer will never be
correct
> again...
> I wonder why it acts like this...
> Can anyone helps me? Thx..
>
> #include <stdio.h>
> #include <stdlib.h>
> #include <time.h>
> main ()
> {
> int ans,h,a,b;
> printf("Enter -1 to end\n");
> do{
> srand(time(NULL));
> a=1+(rand()%9);
> b=1+(rand()%9);
> printf("How much is %d times %d? ",a,b);
> ans=a*b;
> scanf("%d",&h);
> if (ans == h || h != -1)
> printf("Very Good!\n");
> else
> if (ans != h || h != -1){
> do{{
> printf("No. Please try again.\n");
> printf("? ");
> scanf("%d",&h);}
> if (ans == h || h != -1)
> printf("Very Good!\n");} while (ans != h || h != -1);
> }} while (h != -1);
> if (h == -1)
> printf("That's all for now. Bye.");
> return 0;
> }
>
>
>
> if (ans != h || h != -1){
> do{{
> printf("No. Please try again.\n"); ...
...
> however it shows wrong if I enter "-1"...
... mean: if ans!=h OR h!=-1. It's allways true.
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
main ()
{
int ans,h,a,b;
printf("Enter -1 to end\n");
srand(time(NULL));
for (;;) /* forever */
{
a=1+(rand()%9);
b=1+(rand()%9);
printf("How much is %d times %d? ",a,b);
ans=a*b;
for (;;)
{
scanf("%d",&h);
if (h==-1) /* terminate */
{
printf("\nThat's all for now. Bye.");
exit (0);
}
if (ans==h )
{
printf("Very Good!\n");
break;
}
else
printf("No. Please try again.\n");
}
}
}
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