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From: | "DeHackEd" <notgiven AT out DOT com> |
Newsgroups: | comp.os.msdos.djgpp |
References: | <36D00BD6 DOT A01E4BBB AT erols DOT com> |
Subject: | Re: Physical Memory - Newbie question.... |
Lines: | 38 |
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Message-ID: | <m51A2.3770$a02.265@cabot.ops.attcanada.net> |
Date: | Sun, 21 Feb 1999 18:58:54 -0500 |
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NNTP-Posting-Date: | Sun, 21 Feb 1999 23:59:14 GMT |
To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
Reply-To: | djgpp AT delorie DOT com |
Jason Mullins <cyberj23 AT erols DOT com> wrote in message news:36D00BD6 DOT A01E4BBB AT erols DOT com... >Hello All - > >After reading some of the posts about physical memory, I tried to make >this work myself... I didn't have a lot of luck. I'm also very new to >programming.... > >How can I make the function print the return value on the screen? i.e. >printf("Here is your physical memory\n"); etc... here is what I have so >far, but I think im way OFF :) Actually you are. That function, _dpmi_go32_and_so_on_and_so_on is already defined. The proper use of it in 30 seconds or less would be: #include <stdio.h> #include <dpmi.h> int main() { long int bytes; float answer; // get free memory in bytes bytes = _go32_dpmi_remaining_physical_memory(); // calculate to decimal point megabyte answer = (float) bytes / (1024.0 * 1024.0); printf("%f megabytes of ram free\n", answer); return 0; } Don't define that function yourself, it's taken care of in the libraries.
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