From:	robin AT hyperion22 DOT freeserve DOT co DOT uk (Robin Pell)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: Is that bug ?
Date:	Sun, 07 Feb 1999 19:10:33 GMT
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If you're trying to set the buffer to NULLs, you need to use
memset, eg:

#include <stdlib.h>

int main( void )
{
  char buffer[1024];
  memset( buffer, NULL, sizeof( buffer ) );
  return 0;
}

memcpy copies one chunk of memory to another, eg:

#include <stdlib.h>

int main(void)
{
  char buffer1[1024], buffer2[1024];
  memcpy(buffer2, buffer1, sizeof( buffer ) );
  return 0;
}

Hope this helps,

Rob.

On Sat, 06 Feb 1999 11:30:24 +0000, George Lugovoy
<glugovoy AT uic DOT rnd DOT runnet DOT ru> wrote:

>I has a program:
>
>//////////////////////////////////////////////////////////////////////
>#include <stdlib.h>
>
>int main( void )
>{
>  char buffer[1024];
>  memcpy( buffer, NULL, sizeof( buffer ) );
>  return 0;
>}
>//////////////////////////////////////////////////////////////////////
>
>Under DOS, Unix that program is crashed, BUT
>under Windows that program won't crash.
>What is it ? Is that bug ?
>
>- George

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