From:	h2owong AT hknet DOT com (¤ý¤ô)
Newsgroups:	comp.os.msdos.djgpp
Subject:	Question about pass by pointer
Date:	Thu, 17 Sep 1998 08:32:44 GMT
Organization:	Water World
Reply-To:	h2owong AT hknet DOT com
Message-ID:	<3600c4ec.1308545@news.hknet.com>
MIME-Version:	1.0
NNTP-Posting-Host:	202.67.249.239
Lines:	15
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

	void change(char *n){ 
	    *n=70; 
	}
	int main(){
	    char Number=0;
	    printf("Number=%i\n",Number);
	    change(&Number);
	   printf("Number=%i\n",Number);
	   return 0;
	
What I want to ask is that when the address of Number pass to function
"change", the address value will store in var 'n' , but not '*n' ?!

Damn, I don't know how to say it....... :(

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