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Message-Id: | <199808042331.AAA02691@sable.ox.ac.uk> |
Comments: | Authenticated sender is <mert0407 AT sable DOT ox DOT ac DOT uk> |
From: | George Foot <george DOT foot AT merton DOT oxford DOT ac DOT uk> |
To: | Hooman Katirai <hkatirai AT netpart DOT com> |
Date: | Wed, 5 Aug 1998 00:30:30 +0000 |
MIME-Version: | 1.0 |
Subject: | Re: Possible bit shifting bug ... |
Reply-to: | george DOT foot AT merton DOT oxford DOT ac DOT uk |
CC: | djgpp AT delorie DOT com |
On 4 Aug 98 at 14:53, Hooman Katirai wrote: > The following program gives this output. It is as if no bit shifting is > taking place. I recompiled it as a c program and the same results were > obtained: > > Program: > > #include <iostream.h> > main() { > int j=1; > for (int i=0; i<16; i++) { > cout << j; > j << 1; > } > } > > The output is only a series of '1's. No bitshifting ever took place. I think you meant "j <<= 1;". > Guess I'll just have to multiply by two ... until the fix. > Thanks for your time Writing "j * 2;" wouldn't have any effect either ;). You need the assignment: "j *= 2;". -- george DOT foot AT merton DOT oxford DOT ac DOT uk
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