From:	"JAP" <jap AT mundivia DOT es>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Help about INT 21H under inline asm
Date:	Wed, 4 Feb 1998 00:04:26 +0100
Organization:	Unisource Espana NEWS SERVER
Lines:	13
Message-ID:	<6bg3tt$71q$1@talia.mad.ibernet.es>
NNTP-Posting-Host:	ninfovia180.mundivia.es
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

Hi.
I tried to call the  int 21H under inline asm from gcc and i got the program
fall. It caused an internal protection fault under win95.
I want to know if it can be possible to call this interrupt or it's
impossible under protected mode.
Another question is if these lines is correct:
movw $0x7, %%ax;
shl $8, %%ax;
because I can't make anything with AH and I wonder I I can shift 8 bits to
the left and then AH=7 and AL=0 after I make the shift.
Lot of thanks.

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