From:	Oon Lin <sci-okl AT jcu DOT edu DOT au>
Newsgroups:	comp.os.msdos.djgpp
Subject:	fopen() gives Segmentation Fault. Help ?
Date:	Thu, 13 Nov 1997 13:09:05 +1000
Organization:	University of Queensland
Lines:	48
Message-ID:	<Pine.OSF.3.96.971113125536.13260B-100000@barra.jcu.edu.au>
References:	<3 DOT 0 DOT 16 DOT 19971111193131 DOT 35afdc80 AT hem1 DOT passagen DOT se> <3468C09B DOT 436A AT nortel DOT ca>
NNTP-Posting-Host:	cuda.jcu.edu.au
Mime-Version:	1.0
In-Reply-To:	<3468C09B.436A@nortel.ca>
To:	djgpp AT delorie DOT com
DJ-Gateway:	from newsgroup comp.os.msdos.djgpp

I'm having problem using fopen() in DJGPP. What happened is that I made a
first fopen() call to open a file for reading only and that works
fine..and when I call the second fopen() (after I closed the first
fopen())  it just gives me General Protection Fault with Segmentation
violation .... anybody has any ideas ??



// I'm reading in a text file and then write something back to the same
// file. The file access.txt is a text file residing in the same directory
// as my current directory in which I'm doing programming work

// The code snippet

FILE *fileptr ;

// This part works fine. It can open the file
if ((fileptr = fopen("access.txt","r")) == NULL) { 
   printf("Can't open file !\n");
}

// Close the file without doing any file reading
fclose(fileptr);

// Open the same file for writing
fileptr = fopen("access.txt","w") ; // This statement causes Seg Fault

fclose(fileptr); // Program aborts without reaching here ...



Thanks for reading through the code !

Kean

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