From:	Thomas Demmer <demmer AT LSTM DOT Ruhr-UNI-Bochum DOT De>
Newsgroups:	comp.os.msdos.djgpp
Subject:	Re: A newbie question: out to print out value of doubles?
Date:	Mon, 09 Dec 1996 10:20:19 +0100
Organization:	Lehrstuhl fuer Stroemungsmechanik
Lines:	49
Message-ID:	<32ABD9D3.41C6@LSTM.Ruhr-UNI-Bochum.De>
References:	<32a98413 DOT 1518950 AT news DOT diac DOT com> <32A9892D DOT 3AC3 AT cornell DOT edu>
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To:	djgpp AT delorie DOT com
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A. Sinan Unur wrote:
> 
> Richard Adams wrote:
> >
> > void main(void)
> 
> please don't do this. main is supposed to return an int no matter what
> some books tell you.
> 
> > {
> >         double a=3.125978724;
> >
> >
> >         printf("The variable a is:\n\t");
> >         fprintf ("%f\n", &a);
> >
> >         return;
> > }
> >
> > I get an "incompatible pointer type" warning. How can I print out the
> > value of a double-precision floating point variable? Any help at all
> > will be greatly appreciated...:)  Thank you!!
> 
> well, fprintf is not fscanf. when you are using the printf functions you
> only need to specify the name of the variable.

And maybe you should have a look at the info
about fprintf(). The incompatible pointer type
stems from feeding a pointer to a string into it,
when a pointer to a FILE was expected. The warning
about wrong arguments in the ... part of ?(printf|scanf)
functions is only issued if you turn on some warnings.
Best use -Wall to get them all.

-- 
Ciao
Tom

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* Thomas Demmer                                             *
* Lehrstuhl fuer Stroemungsmechanik                         *
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