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From: | Paul Shirley <Paul AT chocolat DOT foobar DOT co DOT uk> |
Newsgroups: | comp.os.msdos.djgpp |
Subject: | Re: how to interpret this... |
Date: | Mon, 2 Dec 1996 23:36:16 +0000 |
Organization: | DrinkSoft |
Lines: | 12 |
Distribution: | world |
Message-ID: | <coUZoAAwf2oyEwxk@chocolat.foobar.co.uk> |
References: | <57ve1o$rfk AT lyra DOT csx DOT cam DOT ac DOT uk> |
NNTP-Posting-Host: | chocolat.foobar.co.uk |
Mime-Version: | 1.0 |
To: | djgpp AT delorie DOT com |
DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
In article <57ve1o$rfk AT lyra DOT csx DOT cam DOT ac DOT uk>, "G.P. Tootell" <gpt20 AT thor DOT cam DOT ac DOT uk> writes >(a==b==c==0) Because all the '==' operators have equal precedence C is allowed to evaluate them in *any* order it likes. About the only one it won't use is a==b && b==c && c==0 ;) since each '==' evaluation reduces its 2 inputs to a boolean value (destroying the value you planned on testing ;) -- Paul Shirley
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