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| From: | Joe Wright <wrightj AT exis DOT net> |
| Newsgroups: | comp.os.msdos.djgpp |
| Subject: | Re: A simple question ... |
| Date: | Sat, 30 Nov 1996 16:11:08 -0500 |
| Organization: | Alpha Solutions |
| Lines: | 21 |
| Message-ID: | <32A0A2EC.4710@exis.net> |
| References: | <57pv9i$142i AT pulp DOT ucs DOT ualberta DOT ca> <32A0AFEC DOT 4E77 AT cs DOT com> |
| Reply-To: | wrightj AT exis DOT net |
| NNTP-Posting-Host: | ppp-1-1.exis.net |
| Mime-Version: | 1.0 |
| To: | fighteer AT cs DOT com |
| DJ-Gateway: | from newsgroup comp.os.msdos.djgpp |
John M. Aldrich wrote:
>
> Gorman Ho wrote:
> >
> > Hey guys.
> >
> > I just wanted to know how many char's a newline character ('\n') is.
> > Is it 2 (10 and 13) or just 1?
>
> Inside your C program, it's 1. In the operating system, it can be any
> of a number of things:
>
> - In DOS, it's a CRLF pair.
> - In Unix, it's just a CR.
> - In Mac, it's something else (can't remember)
>
Shame on you John. In Unix '\n' is 0x0A, a linefeed. '\r' is '0x0D',
the carriage return (CR). But you knew that..
Joe
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