Date:	Thu, 9 May 1996 00:39:01 +0400 (MSD)
From:	"Alexander V. Lukyanov" <lav AT video DOT yars DOT free DOT net>
Message-Id:	<199605082039.AAA15807@video.yars.free.net>
To:	justin AT yoss DOT canweb DOT net, wank AT uebemc DOT siemens DOT de
Cc:	djgpp AT delorie DOT com
Subject:	Re: vararg

> From: Justin Ward <justin AT yoss DOT canweb DOT net>
> 
> On Wed, 8 May 1996, Rainer Wank wrote:
> 
> > void abc(int anzahl, unsigned char abc, ...)
> > {
> >  va_list ap;
> >  va_start(ap, abc);
> >  fg = va_arg(ap, unsigned char);
> >  printf("\n\rErster variabler Parameter: %d", fg);
> >  va_end(ap);
> > }
> 
> You are taking fg as a char, but printing it as an int. With djgpp, and 
> int is 4 bytes and a char is either two or one (I think), depending on 
> whether you're compiling as C or C++. On the sun and on bc 3.1, a char 
> and an int are both 2 bytes it seems. I can't say for sure regarding the 
> sun, but I know this is the case regarding bc. Anyway, just rewrite your 
> printf using %c instead of %d and everything will be fine.

No, this is wrong. char is 1 byte in djgpp and it is automatically
converted to int when passed as a parameter.

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