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Subject:	Re: strtod ("nan") returns negative NaN
To:	cygwin AT cygwin DOT com
References:	<20180814095618 DOT GT3747 AT calimero DOT vinschen DOT de> <20180814095618_dot_GT3747_at_calimero_dot_vinschen_dot_de> <20180814103900 DOT GU3747 AT calimero DOT vinschen DOT de> <20180814 DOT 211757 DOT 2066454831159853501 DOT trueroad AT trueroad DOT jp> <20180814132301 DOT GX3747 AT calimero DOT vinschen DOT de> <1e04c237-70f8-5cc9-7dae-d00e3bfea39d AT avenger DOT ws> <20180814153528 DOT GY3747 AT calimero DOT vinschen DOT de>
From:	Heavenly Avenger <avenger AT avenger DOT ws>
Message-ID:	<c351c1c2-dac0-b4c4-b640-a749ec3254fa@avenger.ws>
Date:	Tue, 14 Aug 2018 13:04:32 -0300
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Well, that's what I get in linux and cygwin for:

#include <stdio.h>
#include <stdlib.h>
#include <math.h> /* the last two printfs requires this */
int main (void) {
   printf ("strtof (\"nan\", NULL) = %f\n", strtof ("nan", NULL));
   printf ("strtof (\"-nan\", NULL) = %f\n", strtof ("-nan", NULL));
   printf ("strtod (\"nan\", NULL) = %f\n", strtod ("nan", NULL));
   printf ("strtod (\"-nan\", NULL) = %f\n", strtod ("-nan", NULL));
   printf ("strtold (\"nan\", NULL) = %Lf\n", strtold ("nan", NULL));
   printf ("strtold (\"-nan\", NULL) = %Lf\n", strtold ("-nan", NULL));
   printf ("nan (\"\") = %f\n", nan (""));
   printf ("-nan (\"\") = %f\n", -nan (""));
}

I get:

Gentoo Linux (native linux)
strtof ("nan", NULL) = nan
strtof ("-nan", NULL) = nan
strtod ("nan", NULL) = nan
strtod ("-nan", NULL) = nan
strtold ("nan", NULL) = nan
strtold ("-nan", NULL) = nan
nan ("") = nan
-nan ("") = -nan

cygwin 2.10.0:
strtof ("nan", NULL) = nan
strtof ("-nan", NULL) = nan
strtod ("nan", NULL) = -nan
strtod ("-nan", NULL) = nan
strtold ("nan", NULL) = -nan
strtold ("-nan", NULL) = -nan
nan ("") = nan
-nan ("") = -nan

So, let's hope the patch does not transform the behavior from the nan 
from math.h.

And yes, you have a good point. Just, well, different people made those 
different parts of the code so, better cygwin follow the ""convention"", 
if we can call it, that. :)


On 8/14/2018 12:35 PM, Corinna Vinschen wrote:
>     printf ("nan (\"\") = %f\n", nan (""));
>     printf ("-nan (\"\") = %f\n", -nan (""));


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