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Date:	Wed, 09 Nov 2011 16:50:37 +0100
From:	Marco Atzeri <marco DOT atzeri AT gmail DOT com>
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To:	cygwin AT cygwin DOT com
Subject:	Re: Pass windows-style paths to the interpreter from the shebang line ?
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On 11/9/2011 2:39 PM, Timothy Madden wrote:
> Hello
>
> I would like to write a php script to run from my cygwin command line.
> I have the php CLI executable (php.exe) in PATH and I use
> #!/bin/env php
> as the first line of the .php script, and make it executable.
>
> The problem is that bash will than invoke the Win32 native php.exe
> binary with the Cygwin-style path of my script as the argument,
> and then php complains that it:
>
> `Could not open input file: /home/Adrian/usr/local/bin/parseLog.php´
>
> Which is normal for php.exe, as it does not understand cygwin paths.
>
> I found no way around this problem. I would type `php /scriptname/´
> myself but then the script name would no longer be searched on PATH and
> I would have to type
> 'D:\Local\cygwin\home\Adrian\usr\local\bin\parseLog.php' as the script
> name at all times.
>
> Is there a way around this ? Can cygwin detect the executable is not a
> cygwin application add pass in the right path name ?
>
> Thank you,
> Timothy Madden
>

you need to use cygpath to convert posix path in window path

You could make a php.sh script like this to invoke your php.exe
with a window path

----------------------------------------------------------
#!/bin/bash
for i in $(echo $PATH | tr ':' ' ')
   do
     a=$(find  $i -name $1 -exec cygpath -w  \{\}    \;  )
     if ( [ "$a" != "" ] ) ; then
       /full_cygwin_path/php.exe $a
       exit
     fi
   done

----------------------------------------------------------

Regards
Marco



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