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From: | Sam Steingold <sds AT gnu DOT org> |
Subject: | creating dynamic libraries |
Date: | Fri, 25 Sep 2009 17:09:43 -0400 |
Lines: | 48 |
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Hi, How do I create a dynamic library which uses data in the executable which uses it? specifically, I have this main program: =================== main.c #include <stdio.h> extern int shared_func (void); int my_int_var = 42; int my_int_addr = &my_int_var; int main (void) { printf("[%d]\n",shared_func()); return 0; } =================== main.c and this shared library: =================== shared.c extern int my_int_var; int shared_func (void) { return my_int_var; } =================== shared.c this is what I get on linux: $ gcc -fPIC -shared -o shared.so shared.c $ gcc -o main main.c shared.so $ LD_LIBRARY_PATH=. ./main [42] however when I try the same trick on cygwin, I get this: $ gcc -shared -o shared.dll shared.c /.../6/cc1e5Kdk.o:shared.c:(.text+0x4): undefined reference to `_my_int_var' so, what do I do? I suppose I could extract my_int_var into a separate shared library, declare it there as __declspec(dllexport), then use it as __declspec(dllimport) in shared.c. alas, this means that my_int_addr fails with "error: initializer element is not constant". so, is there a way to create a dll which would use data in the executable it will be linked against? thanks. Sam. -- Problem reports: http://cygwin.com/problems.html FAQ: http://cygwin.com/faq/ Documentation: http://cygwin.com/docs.html Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple
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