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Date: | Tue, 9 Jun 2009 00:36:48 +0200 |
Message-ID: | <e01d8a50906081536i34f7710bu49588c85e37d2a13@mail.gmail.com> |
Subject: | Re: Bug in $PATH initialization? |
From: | Lennart Borgman <lennart DOT borgman AT gmail DOT com> |
To: | cygwin AT cygwin DOT com |
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On Tue, Jun 9, 2009 at 12:28 AM, ABCD<en DOT ABCD AT gmail DOT com> wrote: > -----BEGIN PGP SIGNED MESSAGE----- > Hash: SHA1 > > Lennart Borgman wrote: >> I am trying to get "bash -i" to start up with $PATH having >> >> =C2=A0 =C2=A0/usr/local/bin:/usr/bin:/bin >> >> at the beginning. I believe I need to do this without any init file >> running so I set the windows Path variable to contain the >> corresponding windows directories first. So I set Path in cmd.exe with >> >> =C2=A0 set Path=3Dc:\cygwin\bin;%Path% >> =C2=A0 set Path=3Dc:\cygwin\usr\bin;%Path% >> =C2=A0 set Path=3Dc:\cygwin\usr\local\bin;%Path% >> >> and then I do >> >> =C2=A0 bash -i >> >> However $PATH starts with >> >> =C2=A0 =C2=A0/usr/local/bin:/usr/bin:/usr/bin >> >> I thought the last dir above should be /bin, not /usr/bin. >> >> Is this intentional or is it a bug. If it is intentional can I somehow >> do what I want another way? >> > > In Cygwin, /bin and /usr/bin both always point to the same place, so it > does get the effect you seem to want, just not in the way you expected. Thanks, but why do I see both /usr/bin and /bin in a cygwin shell started with --login then? -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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