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From: | "John Emmas" <johne53 AT tiscali DOT co DOT uk> |
To: | <cygwin AT cygwin DOT com> |
Subject: | Cygwin struct alignment |
Date: | Wed, 24 Dec 2008 12:16:14 -0000 |
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A program I'm building connects to a (Cygwin) server and receives the address of a shared memory segment. The memory contains an array of struct and you probably know that Microsoft (by default) aligns structure members on 8-byte boundaries (sometimes called 8-byte packing). As things stand, both client and server use System V shared memory and everything works well if I compile under Cygwin or Linux. Ultimately however, there'll be no Linux clients. The clients will either be Cygwin clients or Windows clients. Therefore I'm currently experimenting to see if I can change the server to use Windows shared memory (only under Cygwin of course - not for Linux use). This all seems to be going well - but I was surprised to find that I need to compile the Windows clients using MSVC's default (8-byte) struct alignment. I'd assumed that Cygwin probably wouldn't use structure packing (only because I don't think Linux does). But I only get meaningful data with 8-byte packing. It looks as if Cygwin's compiler must default to 8-byte packing too. Does that make sense? Thanks, John -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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