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Date:	Mon, 14 Apr 2008 21:40:18 -0500
From:	"Yaakov (Cygwin Ports)" <yselkowitz AT users DOT sourceforge DOT net>
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To:	cygwin AT cygwin DOT com
Subject:	Re: [ANNOUNCEMENT] NEW: libtool-2.2.2-2 / Updated: libltdl7-2.2.2-2
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Charles Wilson wrote:
| I think that libtool hasn't been told that LDFLAGS should include
| -L/usr/lib/w32api.  I think this is something that should be passed on
| the invocation line in your makefile -- maybe AM_LDFLAGS needs to be set?

As I'm sure you're aware, /usr/lib/w32api is in ld's default library
path, so -L/usr/lib/w32api should never be necessary.  Nor was it
required with libtool-1.5; this is a regression, but I'm not sure what
the cause is.

In /usr/bin/libtool, I see the following:

sys_lib_search_path_spec="/usr/lib /lib/w32api /lib /usr/local/lib"

which is hard-coded for cygwin in _LT_SYS_DYNAMIC_LINKER (prev.
AC_LIBTOOL_SYS_DYNAMIC_LINKER).  But with the libtool script in the
package I'm trying to build, I find:

sys_lib_search_path_spec="/lib /usr/lib /usr/local/lib"

This didn't happen in another package, so I dug a bit further.  If I run
./config.lt in this particular package, then the correct
$sys_lib_search_path_spec appears, but when I run './config.status
libtool', then I get the latter.

Both packages use CC and CXX tags, and but the one that works correctly
had warnings during autoreconf:

configure.ac:169: warning: LT_OUTPUT was called before LT_LANG
/usr/share/aclocal/libtool.m4:775: LT_LANG is expanded from...
configure.ac:169: the top level
/usr/share/aclocal/libtool.m4:5282: _LT_PROG_CXX is expanded from...
/usr/share/aclocal/libtool.m4:5305: _LT_LANG_CXX_CONFIG is expanded from...
/usr/share/aclocal/libtool.m4:792: _LT_LANG is expanded from...
autoreconf-2.61: configure.ac: tracing
configure.ac:169: warning: LT_OUTPUT was called before LT_LANG
aclocal.m4:790: LT_LANG is expanded from...
configure.ac:169: the top level

where the package with the buggy libtool had no such warnings.

Any ideas?

| $ ./func_win32_libid.sh /usr/lib/w32api/libwinmm.a
| x86 archive import

That's good to know.


Yaakov

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