Mail Archives: cygwin/2008/01/10/18:41:33
On Thu, 10 Jan 2008, Christopher Faylor wrote:
> On Fri, Jan 11, 2008 at 12:13:59AM +0100, Sven K?hler wrote:
> >> bash -c "exec /bin/echo \$@" some arguments here
> >>
> >> and see what's printed; then read the bash man page for why this
> >> happens).
> >
> >Oh, that possibility was new to me.
> >
> >All i wonder, is why the "some" gets lost. Only "arguments here" is
> >printed. And actually i would like to argue, that "$@" instead of $@
> >should be used.
>
> Because, as on linux, the arguments are taken to be argv[0 - 2].
>
> bash -c "exec /bin/echo \"\$0\" \"\$@\""
>
> will get you all of the arguments.
Or, in other words, "read the bash man page for why this happens" (in
particular, the part that talks about the "-c" argument). :-)
Igor
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