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| From: | "Dave Korn" <dave DOT korn AT artimi DOT com> |
| To: | <cygwin AT cygwin DOT com> |
| References: | <AB5E58B87EB73C46A38073D8F459F11335B8D2 AT dataspheresrv01> <4716E9E2 DOT 9030509 AT cwilson DOT fastmail DOT fm> |
| Subject: | RE: Problem with the dos2unix command |
| Date: | Thu, 18 Oct 2007 11:11:54 +0100 |
| Message-ID: | <051c01c8116f$505021d0$2e08a8c0@CAM.ARTIMI.COM> |
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On 18 October 2007 06:07, Charles Wilson wrote:
> Patrick Monnerat wrote:
>> I'm trying to convert a \r\n line-ending file to unix style, but
>> this file has some lines with their last character being \r (i.e.: the
>> sequence of binary bytes is ...\r\r\n...)
>>
>> Using dos2unix to convert it strips both \r, resulting in a byte sequence
>> ...\n...
>>
>> This seems to me a bug. I need the trailing \r in the file as a normal
>> character, not being part of the line ending.
>
> This behavior is by design. What you ask doesn't make much sense for
> most text processing:
But, since it's what Patrick wants:
sed -b -e 's/\r$//g' < infile > outfile
ought to do the trick:
/artimi/chips $ od -c foo
0000000 l \r i n e 1 \r \n l i n e s 2
0000020 \r \r \n l i n e s 3 \r \n
0000034
@_______. .
( /"\
||--||(___)
'" '"'---'
/artimi/chips $ sed < foo -b -e 's/\r$//g' | od -c
0000000 l \r i n e 1 \n l i n e s 2 \r
0000020 \n l i n e s 3 \n
0000031
@_______. .
( /"\
||--||(___)
'" '"'---'
/artimi/chips $
cheers,
DaveK
--
Can't think of a witty .sigline today....
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