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Date: | Sun, 6 Aug 2006 07:46:07 -0800 |
Message-ID: | <74382BAFEAA.000000D2wolfpack@inbox.com> |
From: | Shane <wolfpack AT inbox DOT com> |
Subject: | Checking XCOPY Exit Value in Cygwin Bash |
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Hi all, I am writing a automated build script for my project that will be run under cygwin. I will copy my updated source files to the build directory and if there are updated files, the executables will be built. To copy the source files, I had to use XCOPY since the directory structure should be preserved in the destination directory also. To copy only the updated files, I used the /D switch for XCOPY. Now since I want to execute the source compile only if files in the build directory have been updated, I have to use the exit codes of XCOPY inside the script. I tried checking the value of $! after executing XCOPY but it didnt work. I couldn't find a solution in the internet too. Currently I am piping the standard output to a file and checking if the number of files copied is 0 or not. But I think this is not an elegant solution. This is what I am doing now. [script] copied=false # Helper Function copy_files() { echo copying *.$1 files in $2 to $3\\$2 xcopy /DSYI $2\\*.$1 $3\\$2 | tee copy.log while read amount ; do if [ ${amount::1} != "0" ]; then copied=true; fi done < copy.log } cd ../source copy_files h . ..\\build copy_files c . ..\\build copy_files cpp . ..\\build rm -f copy.log ! $copied && echo "Files up-to-date. Skipping build" && exit 0 cd ../build # Start the Build Process [/script] Can you please provide me a way of checking the XCOPY exit code: reference [http://www.microsoft.com/resources/documentation/windows/xp/all/proddocs/en-us/xcopy.mspx?mfr=true] within Bash? Thank you for your time. Shane -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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