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Date:	Tue, 5 Apr 2005 16:55:57 -0400 (EDT)
From:	Igor Pechtchanski <pechtcha AT cs DOT nyu DOT edu>
Reply-To:	cygwin AT cygwin DOT com
To:	mitch gart <mgart AT kronos DOT com>
cc:	cygwin AT cygwin DOT com
Subject:	Re: sed and searches for $
In-Reply-To:	<loom.20050405T215243-900@post.gmane.org>
Message-ID:	<Pine.GSO.4.61.0504051648310.29048@slinky.cs.nyu.edu>
References:	<loom DOT 20050405T215243-900 AT post DOT gmane DOT org>
MIME-Version:	1.0

On Tue, 5 Apr 2005, mitch gart wrote:

> It seems like sed works differently when searching for end-of-line ($)
> depending if it's launched from a DOS prompt or from inside a shell
> prompt.
> [snip]
>   sed -n  -e /\\$/= junk
> [snip]
> I've been pretty mystefied by this but I'm guessing the reason has
> something to do with the difference between lines terminated by \r\n
> (DOS) and \n (Unix).
>
> Anyway what I want is to write a sed script that recognizes both kinds
> of line separators, and runs correctly from inside the shell.  Can somebody
> tell me how?   Thanks.

It's a bash quoting issue, not a CRLF issue.  Bash recognizes '\' as a
special quote character, so sed only sees *one* backslash when you run
from bash, making it search for a single dollar sign (not what you wanted,
I suspect).  Use single quotes in bash to wrap strings with special
characters.  The following should work from bash:

  sed -n -e '/\\$/=' junk

BTW, this is not in any way Cygwin-specific.
HTH,
	Igor
-- 
				http://cs.nyu.edu/~pechtcha/
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