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Message-ID:	<20030818215453.69513.qmail@web40808.mail.yahoo.com>
Date:	Mon, 18 Aug 2003 14:54:53 -0700 (PDT)
From:	Jim Holder <j_r_holder AT yahoo DOT com>
Subject:	finding out how much memory is available with malloc, gcc, cygwin
To:	cygwin AT cygwin DOT com
MIME-Version:	1.0

A program similar to the one listed below works for me on Linux but not under
Cygwin.  The idea is to find out how memory I can allocate on the machine.  The
Cygwin version keeps going (past 700MB), reporting that it has allocated more
memory than the machine has.  What am I doing wrong?  Thanks.

#include <stdlib.h>
#include <stdio.h>
int main(void)
{
    char *p;
    int loop = 1;
    long allocated = 0L;
    const long PIECE = 1000L;
    const long TENMB = 10000000L;
    long nextTenMB = TENMB;

    while(loop)
    {
        p = (char*)malloc(PIECE);
        if(p == NULL)
        {
            printf("p == NULL\n");
            loop = 0;
        }
        if(p == (char*)0)
        {
            printf("p == (char*)0\n");
            loop = 0;
        }
        if(loop == 0)
            break;
        allocated += PIECE;
        if(allocated >= nextTenMB)
        {
            printf("%ld\n", allocated);
            nextTenMB += TENMB;
        }
    }
    printf("final:  %ld\n", allocated);
    return 0;
}

Some environment particulars:

    -  cygwin 1.3.19-1
    -  gcc 3.2-3
    -  windows 2000, version 5.0, service pack 4

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