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From:	"Lisbeth Kellogg" <lisbeth DOT kellogg AT apioutsourcing DOT com>
To:	"'Lisbeth Kellogg'" <lisbeth DOT kellogg AT apioutsourcing DOT com>,
	<cygwin AT cygwin DOT com>
Subject:	RE: Problem call a cygwin command from a dos batch file
Date:	Tue, 29 Jul 2003 16:25:58 -0500
Message-ID:	<006501c35618$0056d3c0$9901020a@api360.net>
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X-OriginalArrivalTime:	29 Jul 2003 21:20:33.0985 (UTC) FILETIME=[3F20B310:01C35617]

I guess I found the answer to my own question.  Since some other people
have had this same problem, here is the solution.  

There is a problem with the PATH environment under Win 2000.  To
identify the problem I typed the following in DOS:

     bash -c "which sort"

I got a response of "/cygdrive/c/WINNT/system32/sort" instead of
"/usr/bin/sort".  This is the DOS sort command, not the cygwin sort
command.  I just had to change my command to:

     bash -c "c:/cygwin/bin/sort -t \| -k 3 -k 11 -k 12 -o
sortedfile.txt unsortedfile.txt"

This could be a problem any time the DOS and cygwin commands have the
same name.

---
Lisbeth Kellogg
Office: 651-675-2610
 

-----Original Message-----
From: cygwin-owner AT cygwin DOT com [mailto:cygwin-owner AT cygwin DOT com] On Behalf
Of Lisbeth Kellogg
Sent: Tuesday, July 29, 2003 3:06 PM
To: cygwin AT cygwin DOT com
Subject: Problem call a cygwin command from a dos batch file


I am having a problem with trying to sort a pipe-delimited file using
the cygwin sort command from a dos batch file.  If I enter the command
in cygwin environment, it works fine:

     sort -t \| -k 3 -k 11 -k 12 -o sortedfile.txt unsortedfile.txt

But I have problems running it from a dos batch file.  It appears to
work in Windows XP but not in Windows 2000.  The command in the batch
file is:

     bash -c "sort -t \| -k 3 -k 11 -k 12 -o sortedfile.txt
unsortedfile.txt"

In Win XP it executes without a problem, but in Win 2000, I get a
message the says, "Input file specified two times," as if it does not
recognize the -o option.  If I put the sort command in an echo, I get
the results I would expect, so the -o is not lost:

     bash -c "echo sort -t \| -k 3 -k 11 -k 12 -o sortedfile.txt
unsortedfile.txt"

Rearranging the arguements and adding extra escape characters in various
combinations don't seem to help.

Any ideas, please?

---
Lisbeth Kellogg
Office: 651-675-2610
 


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