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| From: | "Lisbeth Kellogg" <lisbeth DOT kellogg AT apioutsourcing DOT com> |
| To: | <cygwin AT cygwin DOT com> |
| Subject: | Problem call a cygwin command from a dos batch file |
| Date: | Tue, 29 Jul 2003 15:06:09 -0500 |
| Message-ID: | <005401c3560c$d9d29a00$9901020a@api360.net> |
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| X-OriginalArrivalTime: | 29 Jul 2003 20:00:45.0378 (UTC) FILETIME=[18E54220:01C3560C] |
I am having a problem with trying to sort a pipe-delimited file using
the cygwin sort command from a dos batch file. If I enter the command
in cygwin environment, it works fine:
sort -t \| -k 3 -k 11 -k 12 -o sortedfile.txt unsortedfile.txt
But I have problems running it from a dos batch file. It appears to
work in Windows XP but not in Windows 2000. The command in the batch
file is:
bash -c "sort -t \| -k 3 -k 11 -k 12 -o sortedfile.txt
unsortedfile.txt"
In Win XP it executes without a problem, but in Win 2000, I get a
message the says, "Input file specified two times," as if it does not
recognize the -o option. If I put the sort command in an echo, I get
the results I would expect, so the -o is not lost:
bash -c "echo sort -t \| -k 3 -k 11 -k 12 -o sortedfile.txt
unsortedfile.txt"
Rearranging the arguements and adding extra escape characters in various
combinations don't seem to help.
Any ideas, please?
---
Lisbeth Kellogg
Office: 651-675-2610
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