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| Message-ID: | <3EA06290.5070308@nordrhein.de> |
| Date: | Fri, 18 Apr 2003 22:39:44 +0200 |
| From: | Armin Diehl <diehl AT nordrhein DOT de> |
| User-Agent: | Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.4a) Gecko/20030401 |
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| To: | cygwin AT cygwin DOT com |
| Subject: | Re: dll creation |
| References: | <3EA02548 DOT 8040308 AT nordrhein DOT de> <Law10-OE40ivee6v3xk000050df AT hotmail DOT com> |
| In-Reply-To: | <Law10-OE40ivee6v3xk000050df@hotmail.com> |
Martin wrote:
> Please display the code that calls the DLL and how it calls the DLL
function
it is a simple call hello. Because hello has no params, the calling
convention dosent matter. It is not a calling convention problem because
it crashed in hello and never returned.
> see bottom
> ----- Original Message -----
> From: "Armin Diehl" <diehl AT nordrhein DOT de>
> To: <cygwin AT cygwin DOT com>
> Sent: Friday, April 18, 2003 9:18 AM
> Subject: dll creation
>
>
>
>>i tried a small sample and i always get a protection fault in
>>cygwin1.dll if i call the funtion in the dll:
>>
>>#include <stdio.h>
>>
>>int hello ()
>>{
>> printf ("hello\n");
>>}
>>
>>gcc -c test.c
>>gcc -shared -o test.dll test.o
>>
>>will create the dll. If hello is called, i get a protection fault in
>>cygwin1.dll at 000C8C81, Read of address 00000144.
>>
>>I already updated everything today. This happens on xp. Is there some
>>kind of init needed ? (Btw, the calling program does not use the cygwin
>
> dll)
>
>>gcc --verion: gcc (GCC) 3.2 20020927 (prerelease)
>>ld -V: GNU ld version 2.13.90 20030308
>>
>>
>>
>
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