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Message-ID: | <3EA06290.5070308@nordrhein.de> |
Date: | Fri, 18 Apr 2003 22:39:44 +0200 |
From: | Armin Diehl <diehl AT nordrhein DOT de> |
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To: | cygwin AT cygwin DOT com |
Subject: | Re: dll creation |
References: | <3EA02548 DOT 8040308 AT nordrhein DOT de> <Law10-OE40ivee6v3xk000050df AT hotmail DOT com> |
In-Reply-To: | <Law10-OE40ivee6v3xk000050df@hotmail.com> |
Martin wrote: > Please display the code that calls the DLL and how it calls the DLL function it is a simple call hello. Because hello has no params, the calling convention dosent matter. It is not a calling convention problem because it crashed in hello and never returned. > see bottom > ----- Original Message ----- > From: "Armin Diehl" <diehl AT nordrhein DOT de> > To: <cygwin AT cygwin DOT com> > Sent: Friday, April 18, 2003 9:18 AM > Subject: dll creation > > > >>i tried a small sample and i always get a protection fault in >>cygwin1.dll if i call the funtion in the dll: >> >>#include <stdio.h> >> >>int hello () >>{ >> printf ("hello\n"); >>} >> >>gcc -c test.c >>gcc -shared -o test.dll test.o >> >>will create the dll. If hello is called, i get a protection fault in >>cygwin1.dll at 000C8C81, Read of address 00000144. >> >>I already updated everything today. This happens on xp. Is there some >>kind of init needed ? (Btw, the calling program does not use the cygwin > > dll) > >>gcc --verion: gcc (GCC) 3.2 20020927 (prerelease) >>ld -V: GNU ld version 2.13.90 20030308 >> >> >> > -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Problem reports: http://cygwin.com/problems.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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