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Message-ID:	<3E922BD0.4080206@rfk.com>
Date:	Mon, 07 Apr 2003 21:54:24 -0400
From:	"Larry Hall (RFK Partners, Inc.)" <lhall AT rfk DOT com>
Reply-To:	lhall AT rfk DOT com
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To:	Martin <mgainty AT hotmail DOT com>
CC:	vxj45 AT hotmail DOT com, cygwin AT cygwin DOT com
Subject:	Re: Using two versions of cygwin1.dll
References:	<29950-2200341723349124 AT M2W067 DOT mail2web DOT com> <OE30U1KPhht0lLRa8170001a444 AT hotmail DOT com>
In-Reply-To:	<OE30U1KPhht0lLRa8170001a444@hotmail.com>

Martin,

You can't simply load 2 Cygwin DLLs via LoadLibrary.  And you can't
run two different versions of the Cygwin DLL simultaneously whether you
dynamically load them or not.  I guess I was a little too obtuse when I
mentioned that there isn't a way to do this.  Sorry.  I'll try to more
explicit next time. ;-)

Larry


Martin wrote:
> Technically you can call LoadLibrary for the specific DLL Resource location
> which you are loading
> Which means you will have to download the source ; Create the Invoking App
> and put the fix in yourself..
> and test the invocation for all conditions
> Not a trivial task-
> GL,
> Martin
> Wise man says you can do anything if you're willing to do the work
> yourself..
> 
> ----- Original Message -----
> From: <lhall AT pop DOT ma DOT ultranet DOT com>
> To: <vxj45 AT hotmail DOT com>; <cygwin AT cygwin DOT com>
> Sent: Monday, April 07, 2003 4:34 PM
> Subject: RE: Using two versions of cygwin1.dll
> 
> 
> If you have to ask, the answer is no.  You might want
> to check the email archives for discussions about this
> topic if you're interested in finding out more details.
> 
> Larry
> 
> Original Message:
> -----------------
> From: Vishal Jain vxj45 AT hotmail DOT com
> Date: Mon, 07 Apr 2003 16:28:00 -0700
> To: cygwin AT cygwin DOT com
> Subject: Using two versions of cygwin1.dll
> 
> 
> I am running my program from cygwin shell.
> My program uses a customized version of the cygwin1.dll
> Can I have two versions of dll one for the shell and one for my program and
> invoke my program from the (shell)command prompt?
> 
> thanks,
> Vishal



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