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Date: | Mon, 11 Feb 2002 16:09:39 -0800 |
To: | wally liau <wally_2nd AT yahoo DOT com>, cygwin AT cygwin DOT com |
From: | Randall R Schulz <rrschulz AT cris DOT com> |
Subject: | Re: HELP: java path and classpath question |
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Wally, Unless a program has been ported to and compiled with Cygwin headers and libraries it is a Windows program and knows nothing of POSIX (Unix-style) file names and PATH (-type) variables. Cygwin programs will understand both kinds of arguments. To be more precise, the Cygwin libraries take either kind of file name, but a program that was only minimally ported to Cygwin might make its own assumptions about what a file name looks like, and could misinterpret a Windows-style name. The Java tools from Sun have _not_ been ported to Cygwin, and hence you must supply arguments in the Windows format. Good luck. Randy At 14:39 2002-02-11, you wrote: >He Randall, thanks a lot for the message. > >The java compiler I am using is called generic java (with extended utility >classes, see http://www.research.avayalabs.com/user/wadler/pizza/gj/and >http://developer.java.sun.com/developer/earlyAccess/adding_generics/). > > >those environment variables and alias are set in .bashrc. "gjc" is >supposed to compile java source files containing templates into stardard >class files. > >I am confused with cygwin- and window-style paths. A simple question is >which style to use in order to invoke window java vm, and if window-style >path is the one to be used, how to put it in a file like .bashrc. > >Thanks again. -- Unsubscribe info: http://cygwin.com/ml/#unsubscribe-simple Bug reporting: http://cygwin.com/bugs.html Documentation: http://cygwin.com/docs.html FAQ: http://cygwin.com/faq/
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