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| Message-ID: | <80575AFA5F0DD31197CE00805F650D7602CFF4@wilber.adroit.com> |
| From: | "Robinow, David" <drobinow AT dayton DOT adroit DOT com> |
| To: | "'cygwin AT cygwin DOT com'" <cygwin AT cygwin DOT com> |
| Subject: | RE: Makefile that runs w.o. changes on Cygwin & Linux: how to do |
| "rm -f $(TARGET)"? | |
| Date: | Thu, 6 Sep 2001 17:39:10 -0400 |
| MIME-Version: | 1.0 |
| X-Mailer: | Internet Mail Service (5.5.2650.21) |
MACH=`uname -s`
case "${MACH}" in
CYGWIN*)
EXE=".exe"
;;
*)
EXE=""
;;
esac
rm -f thing${EXE}
> -----Original Message-----
> From: Karr, David [mailto:david DOT karr AT cacheflow DOT com]
> Sent: Thursday, September 06, 2001 4:38 PM
> To: 'cygwin AT cygwin DOT com'
> Subject: Makefile that runs w.o. changes on Cygwin & Linux: how to do
> "rm -f $(TARGET)"?
>
>
> I have a little test application that I want to build and run
> without change
> on Cygwin and Linux. It almost works perfectly, except for
> the "clean"
> target. Is there any way to reference "thing" and have it
> mean "thing" on
> Linux, but "thing.exe" on Cygwin?
--
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