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Message-ID:	<2C08D4EECBDED41184BB00D0B74733420473EDF0@exchanger.cacheflow.com>
From:	"Karr, David" <david DOT karr AT cacheflow DOT com>
To:	"'cygwin AT cygwin DOT com'" <cygwin AT cygwin DOT com>
Subject:	RE: Pipe "make" stdout and stderr to process?
Date:	Thu, 5 Jul 2001 15:10:12 -0700
MIME-Version:	1.0
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That did it, thanks.  I didn't notice an example of this in the Bash man
page.

-----Original Message-----
From: Randall R Schulz [mailto:rrschulz AT cris DOT com]
Sent: Thursday, July 05, 2001 3:01 PM
To: Karr, David; 'cygwin AT cygwin DOT com'
Subject: Re: Pipe "make" stdout and stderr to process?


David,

It's somewhat counterintuitive by comparison to the ordering required in 
the absence of a pipe, but you have to merge stderr (2) into stdout (1) 
before the pipe symbol:

         make 2>&1 |filterprog

Randall Schulz


At 14:13 2001-07-05, Karr, David wrote:
>How do I run "make" so I can pass both stdout and stderr to a filtering
>process?  I'm familiar with writing the output to a file, taking both
stdout
>and stderr ("make > make.out 2>&1"), but I don't see how to get this to
work
>if I just want to pipe the output (both stdout and stderr) to another
>process.  When I do "make | filterprog 2>&1", it seems to have no effect,
in
>that it appears as if the stderr from "make" goes directly to the console.
> >From reading the "bash" man page, it almost seems as if redirection
doesn't
>apply to piping.
>
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